Bus prob glib one?

A bus started from the bus stand at 8 AM and after staying 30 minutes at a destination returns back to the bus stand. The Destination is 27 miles from the bus stand. The Speed of the bus is 18mph. In the return pass through the bus travels with 50% vigorous speed.

How do i receive to ucla from...

Answers: if u are tryin to ask, at wat time does the bus get rear legs.

the formula is tht TIME =DISTANCE/SPEED

towards the destination:
27/18 =1.5;
1.5*60=90 which is 1 hour and 30 mins
so the bus reach the destination at 9.30 AM

Stays nearby for 30 mins and strats at 10 AM again

this time at a speed 50% more.
so its 18+18*50%; which is 27

and so again applyin the above formula
27/27=1hour

hence the bus reach the bus stand at 11AM

Is here a dependence someone does that...

My brain hurts only from trying to figure out what the give somebody the third degree is here. But wait!! There isn't one, of late really bad english!

"the bus travels beside 50% fast speed" .......huh?

Sorry kiddo, I similar to problems like these, but your description doesn't cause sense, and there is no interview for anyone to try to answer.

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Bus prob flowing one?

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